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Palindrome Partitioning

Ashish

Ashish Pratap Singh

medium

Problem Description

Solve it on LeetCode

Approaches

1. Backtracking

Intuition:

The core idea is to use backtracking to generate all possible partitioning of the string, and for each partitioning, check if the substrings are palindromes. Backtracking is well-suited for this type of problem because we can recursively try each possible partition and backtrack if it does not lead to a solution.

  1. Start from the beginning of the string and for each character at position i, check if the substring from the start to i is a palindrome.
  2. If it is a palindrome, recursively partition the rest of the string from i+1.
  3. If a partitioning of the entire string is found, add it to the result list.

Code:

2. Dynamic Programming + Backtracking

Intuition:

We can optimize the palindrome checking part by using dynamic programming (DP). Using a 2D DP array, we can store the palindrome status of substrings to avoid recomputing this information repeatedly.

  1. Precompute a 2D array dp where dp[i][j] is true if the substring s[i:j+1] is a palindrome.
  2. Use this DP table in the backtracking process to quickly check if a substring is a palindrome.

Code: